[R] help with data.frame
arun
smartpink111 at yahoo.com
Tue May 21 21:02:21 CEST 2013
Hi,
library(stringr)
b[str_detect(colnames(b),"^y")]
# y y.1 y.2
#1 0.00000 0.000000 0.000000
#2 19.55811 17.023812 15.354880
#3 10.74991 9.024250 8.177128
#4 5.91924 4.789331 4.367188
#or
b[,!is.na(match(gsub("\\..*","",names(b)),"y"))]
# y y.1 y.2
#1 0.00000 0.000000 0.000000
#2 19.55811 17.023812 15.354880
#3 10.74991 9.024250 8.177128
#4 5.91924 4.789331 4.367188
A.K.
Dear All
I have the following code for list "a":
a <-list(structure(c(0, 4, 8, 12, 0, 19.5581076131386, 10.7499105081144,
5.91923975728553, 0, 4.08916328337685, 2.26872955281708, 1.24929641535359
), .Dim = c(4L, 3L), .Dimnames = list(NULL, c("time", "y", "b"
)), istate = c(2L, 107L, 250L, NA, 5L, 5L, 0L, 52L, 22L, NA,
NA, NA, NA, 0L, 1L, 1L, NA, NA, NA, NA, NA), rstate = c(0.867511261090201,
0.867511261090201, 12.7772879103809, 0, 0), lengthvar = 2L, class = c("deSolve",
"matrix"), type = "lsoda"), structure(c(0, 4, 8, 12, 0, 17.0238115689622,
9.02425032330714, 4.7893314106951, 0, 4.45067278743554, 2.37140075611636,
1.25855947034654), .Dim = c(4L, 3L), .Dimnames = list(NULL, c("time",
"y", "b")), istate = c(2L, 106L, 251L, NA, 4L, 4L, 0L, 52L, 22L,
NA, NA, NA, NA, 0L, 1L, 1L, NA, NA, NA, NA, NA), rstate = c(0.662055762167652,
0.662055762167652, 12.3096826617166, 0, 0), lengthvar = 2L, class = c("deSolve",
"matrix"), type = "lsoda"), structure(c(0, 4, 8, 12, 0, 15.3548797334796,
8.17712839316703, 4.36718847853436, 0, 5.15624657530424, 2.77411694866808,
1.48166036763212), .Dim = c(4L, 3L), .Dimnames = list(NULL, c("time",
"y", "b")), istate = c(2L, 108L, 260L, NA, 5L, 5L, 0L, 52L, 22L,
NA, NA, NA, NA, 0L, 1L, 1L, NA, NA, NA, NA, NA), rstate = c(0.735884123193699,
0.735884123193699, 12.1878866053931, 0, 0), lengthvar = 2L, class = c("deSolve",
"matrix"), type = "lsoda"))
then I convert it to "b"
b <-data.frame(a)
and manually I would extract the y variables (y, y.1 and y.2) as follows
d <-t(cbind(b$y,b$y.1,b$y.2))
Currently I only have 3 y variables, so manual solution is very
easy. I would like to ask if you have any thoughts on how I could
"automate" (or extract all ys) this so that I could achieve the same
goal even if I have 5000 ys (from y, y.1, y.2.... to y.5000) or any
other number of ys for that matter with a simple code (as opposed to
something like d <-t(cbind(b$y,b$y.1,b$y.2,....b$y.5000))).
your help is greatly appreciated,
thanks,
Andras
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