[R] two questions re: the use of lattice (Q1 SOLVED, not Q2)

[Ranjan Maitra]

On Sun, 22 Jul 2012 15:04:36 -0700 Peter Ehlers <ehlers at ucalgary.ca>
wrote:

> On 2012-07-22 09:02, Ranjan Maitra wrote:
> > Dear friends,
> >
> > Many thanks to Jim (Holtman) and David (Carlson) for their quick
> > responses: Q1 is now solved. There are two almost equivalent ways for
> > doing this. They follow:
> > library(lattice)
> >
> > z <- rbind(cbind(z, 0), cbind(z, 20), cbind(z, 40))
> > z <- cbind(z, rnorm(n = nrow(z)))
> > z <- as.data.frame(z)
> > names(z) <- c("Method", "sigma", "INU", "Error")
> > sigma <- as.numeric(levels(z$sigma))
> > sigmaExprList <- lapply(sigma, function(s) bquote(italic(sigma) == .
> > (s))) sigmaExpr <- as.expression(sigmaExprList)
> >
> > z$Method <- factor(z$Method, levels = c("BIC", "ICL", "s_v", "Q_v",
> >    "sig-q", "s_lsk", "s_lML", "s_mlsk", "s_mlML", "s_la8", "s_haar"))
> >
> > bwplot(Error~Method | sigma, data = z[z[,"INU"] == 0,
> >                                 ],scales=list(rot=90),
> >         horiz = F, xlab = "Method", ylab = "Relative Error",
> >         strip = function(which.given, which.panel, var.name,
> >           strip.levels = FALSE,
> >           strip.names = TRUE, ...) {
> >           strip.default(which.given, which.panel,
> >                         var.name = sigmaExpr[which.panel],
> >                         strip.levels = FALSE,
> >                         strip.names = TRUE, ...)
> >          },
> >          layout = c(1, 5),  col = "red")
> >
> > # On the other hand, if we do not want to change z$Method in perpetuity, we could do the following:
> >
> >
> > z <- cbind(rep(c("BIC", "ICL", "s_v", "Q_v", "sig-q",
> >                        "s_lsk", "s_lML", "s_mlsk", "s_mlML", "s_la8",
> > "s_haar"), each = 250), rep(c(5, 10, 20, 30, 50), each = 50))
> > z <- rbind(cbind(z, 0), cbind(z, 20), cbind(z, 40))
> > z <- cbind(z, rnorm(n = nrow(z)))
> > z <- as.data.frame(z)
> > names(z) <- c("Method", "sigma", "INU", "Error")
> > sigma <- as.numeric(levels(z$sigma))
> > sigmaExprList <- lapply(sigma, function(s) bquote(italic(sigma) == .
> > (s))) sigmaExpr <- as.expression(sigmaExprList)
> >
> > bwplot(Error~factor(Method, levels = unique(Method)) | sigma, data = z[z
> > [,"INU"] == 0, ],scales=list(rot=90),
> >         horiz = F, xlab = "Method", ylab = "Relative Error",
> >         strip = function(which.given, which.panel, var.name,
> >           strip.levels = FALSE,
> >           strip.names = TRUE, ...) {
> >           strip.default(which.given, which.panel,
> >                         var.name = sigmaExpr[which.panel],
> >                         strip.levels = FALSE,
> >                         strip.names = TRUE, ...)
> >          },
> >          layout = c(1, 5),  col = "red")
> >
> >
> >
> > # However, I am unable to solve Q2. Actually, even more basic is the fact that I can not get Box-Whisker plots without anything else. David's suggestion of using useOuterStrips appears reasonable, but as I said, I can not get anything meaningful even before then.
> >
> > # Try:
> >
> > bwplot(Error~Methods | sigma + INU, data = z,scales=list(rot=90))
> >
> > Any suggestions?
> 
> [I had to dig back to see what your Q2 was. It's good to keep context.]
> 
> Try this:
> 
>   p <- bwplot(Error~Method | sigma + INU, data = z,
>          scales = list(rot=90), horiz = FALSE,
>          layout = c(5,3), col = "red")
> 
>   require(latticeExtra)
>   useOuterStrips(p,
>        strip = <<your sigma-strip function>>,
>        strip.left = strip.custom(
>            var.name = "INU", sep = " = ",
>            strip.names = TRUE)
>   )
> 

This works!! Thanks very much!! May I also ask how I can put in a "%"
after the INU value? i.e., I want the labels to be INU = 0%, INU = 20%,
INU = 40% (instead of INU = 0, INU = 20 and INU = 40).

Many thanks again!
Ranjan

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