[R] replacing NaN for every attribute in my data
mishkind
mishkind at gmail.com
Wed Jul 11 20:36:48 CEST 2012
Hi,
I have a list called ds which has the following attributes:
attributes(ds)
$names
[1] "adj.r.squared" "fstatistic" "intercept" "slope"
[5] "std.error" "tstatistic"
I want to replace all the NaN is ds with 0, and after searching past posts I
found I can hardcode it like this:
ds$adj.r.squared=replace(ds$adj.r.squared,is.nan(ds$adj.r.squared),0)
ds$fstatistic=replace(ds$fstatistic,is.nan(ds$fstatistic),0)
...
ds$tstatistic=replace(ds$tstatistic,is.nan(ds$tstatistic),0)
But, there has to be a more elegant/general solution. I've tried messing
around with lapply but can't seem to get it to work.
Any suggestion?
thanks,
mishkin
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