[R] R object as a function

[Duncan Murdoch]

On 22/01/2008 6:51 AM, Thomas Steiner wrote:
> Okay, let me try to better say what I meant:
> 
> myfun1<-function(x=5,pa) {
>   return(pa[1]*x^2+pa[2]*x+pa[3])
> }
> myfun2<-function(x=5,param,myfunk1) {
>   return(param[1]*myfunk1(x)+param[2]*myfunk1(x))
> }
> test<-function(pars1,pars2,lo,up){
>   mf=myfun1(x=2,pa=8*pars1)
>   integ=integrate(f=myfun2,lower=lo,upper=up,param=pars2,myfunk1=mf)
>   return( 2*integ$value )
> }
> test(pars1=c(1,2,3),pars2=c(-1,1),lo=2,up=7)
> 
> So the function myfun2 will be integrated and has a function (myfunk1)
> itself as an argument.

You're not passing a function as myfunk1, you're passing mf, which is 
the result of evaluating myfun1, so it's a numeric vector.

Duncan Murdoch

> Why is this not possible?
> Thanks,
> Thomas
> 
> PS: the "x=5" and "pa=8*" has no influence...
> 
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