[R] applying a function to data frame columns

[Henrique Dallazuanna]

One thing is needed:

names(v) <- names(u)



PS:Thanks Mark Leeds

On 22/02/2008, Henrique Dallazuanna <wwwhsd at gmail.com> wrote:
> Try this:
>
>  sapply(names(u), function(x)u[x][u[x] >=min(v[x]) & u[x] <= max(v[x])])
>
>
>  On 21/02/2008, dxc13 <dxc13 at health.state.ny.us> wrote:
>  >
>  >  useR's,
>  >
>  >  I want to apply this function to the columns of a data frame:
>  >
>  >  u[u >= range(v)[1] & u <= range(v)[2]]
>  >
>  >  where u is the n column data frame under consideration and v is a data frame
>  >  of values with the same number of columns as u.  For example,
>  >  v1 <- c(1,2,3)
>  >  v2 <- c(3,4,5)
>  >  v3 <- c(2,3,4)
>  >  v <- as.data.frame(cbind(v1,v2,v3))
>  >
>  >  uk1 <- seq(min(v1) - .5, max(v1) + .5, .5)
>  >  uk2 <- seq(min(v2) - .5, max(v2) + .5, .5)
>  >  uk3 <- seq(min(v3) - .5, max(v3) + .5, .5)
>  >
>  >  u <- do.call("expand.grid", list(uk1,uk2,uk3))
>  >
>  >  Here, there are 3 columns; instead of hard-coding this, can the function
>  >  given above, which will restrict the u data frame to values within the
>  >  ranges of each variable, be done with the apply function?  Thanks in
>  >  advance.
>  >
>  >  dxc13
>  >
>  >  --
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>
>
> --
>  Henrique Dallazuanna
>  Curitiba-Paraná-Brasil
>  25° 25' 40" S 49° 16' 22" O
>


-- 
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O