[R] When I cbind the POSIXct gets lost

[Ken Spriggs]

Gabor - Thanks.  I can recreate your example without any problem but I don't
understand the relevance.  
Is turning the result of the cbind() into a dataframe what you're telling
me?  If so, I tried that and I'm still stuck with the loss of the POSIXct. 
(If not I'm afraid I missed the point.)  



Gabor Grothendieck wrote:
> 
> Use data.frame:
> 
>> tt <- ISOdate(2000, 1:3, 1)
>> cbind(tt, tt)
>             tt        tt
> [1,] 946728000 946728000
> [2,] 949406400 949406400
> [3,] 951912000 951912000
>> data.frame(tt, tt)
>                    tt                tt.1
> 1 2000-01-01 12:00:00 2000-01-01 12:00:00
> 2 2000-02-01 12:00:00 2000-02-01 12:00:00
> 3 2000-03-01 12:00:00 2000-03-01 12:00:00
> 
> 
> On Feb 8, 2008 4:59 PM, Ken Spriggs <ksspriggs at gmail.com> wrote:
>>
>> I would like to create a new dataframe from the DateTime column of an
>> existing dataframe and a numeric vector.  When I do cbind(x[,1], y) the
>> result is:
>>
>> [1,] 1199370600     12.500
>> [2,] 1199371200     69.375
>> [3,] 1199371800     23.750
>>
>> where the first column you see used to look like:
>>  "2008-01-03 08:30:00 Central Standard Time"
>>  "2008-01-03 08:40:00 Central Standard Time"
>>  "2008-01-03 08:50:00 Central Standard Time"
>>
>> How do I keep the DateTime from getting converted?  I've tried
>> as.POSIXct()
>> to convert it back (no luck).
>>
>>
>> --
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>>
>> ______________________________________________
>> R-help at r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
> 
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
> 
> 

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