[R] Using lapply and list names not available
john seers (IFR)
john.seers at bbsrc.ac.uk
Tue Feb 5 17:47:16 CET 2008
Hi Gabor
Thanks for the suggestion but I am not sure it actually addresses my
problem. I will ponder the idea of my data needing to be in a different
form but I am not sure how to get there easily with what I have got.
The example I gave was just a simplified example to demonstrate how you
cannot access the names of the list once it has been passed by lapply.
My real world problem is data coming from 4 spreadsheets for thirteen
volunteers and 250 variables with various models being calculated and
values extracted from the models.
lapply seems to be the way to do these repetitive processes on the data,
volunteers etc but then I end up with a load of lists of lists. I guess
I could extract the data from the lists into a more suitable format for
plotting but as lapply has already done all the work it seems a lot of
extra effort. I would like to be able to do one more lapply to plot the
data (or whatever) and be able to slap a label on it so I can keep track
of what I am doing.
Regards
John Seers
-----Original Message-----
From: Gabor Grothendieck [mailto:ggrothendieck at gmail.com]
Sent: 05 February 2008 16:17
To: john seers (IFR)
Cc: R Help
Subject: Re: [R] Using lapply and list names not available
The problem is your data is in wide format and you want it in long
format.
See ?reshape and also see the reshape package. In your example, ?stack
is sufficient:
library(lattice)
xyplot(values ~ seq_along(values) | ind, data = stack(people))
On Feb 5, 2008 11:05 AM, john seers (IFR) <john.seers at bbsrc.ac.uk>
wrote:
>
> Hello All
>
> Using lapply and ending up with lists of lists I often end up in the
> position of not having the names of the list passed by lapply. So, if
> I am doing something like a plot, and I would like the title to
> reflect which plot it is, I cannot easily do it. So I find myself
> doing some unstructured variable passing and counting to be able to
> keep track of my data. Then I think perhaps I should not use lapply
> and just use simple loops.
>
> Is there a better way to do this?
>
> Here is a simple example to illustrate what I am talking about. The
> list has the names of people and I need the names to use as the
> headings of the plots.
>
>
>
> ######################################################################
> ##
> #########
>
> # Make some test data
> people<-list(Andrew=rnorm(10), Mary=rnorm(10), Jane=rnorm(10),
> Richard=rnorm(10))
>
>
> # Function to plot each list entry with its title name
> doplot<-function(individual, peoplenames) {
> peoplecount<<-peoplecount + 1
> plot(individual, main=peoplenames[peoplecount]) }
>
> #
> peoplecount<-0
> jpeg(file="test.jpg")
> par(mfrow=c(2,2))
> lapply(people, doplot, names(people))
> dev.off()
>
> ######################################################################
> ##
> #############
>
>
> Thank you for any suggestions.
>
>
> John Seers
>
> ---
>
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