[R] help please

[Uwe Ligges]

You got at least two answers on this yesterday. If you want more precise 
answers, please tell us what your expected result is.

Uwe Ligges


osita k ezeh wrote:
> hello,
> 
> please can anyone help me out. Am a new user of R
> program. Am having problem
> with this code below, not getting the expected
> results.
> 
>  Each m, the cumulative sum should be 1.000 but the
> 2nd and 3rd m returned 2.000 and 3.000
> instead of 1.000.
> 
> 
> 
> thanks
> Aruike
> 
> 
> 
> pp=function(x,n,M){z=1.0;a=2.3071430;b=7.266064;H=3
> 
>      out.h=c()   
> 
>      out.y=c()
> 
>      out.m=c()
> 
>      out.prob=c()
> 
>      
> 
>        for(h in 1:H){
> 
>        for(m in 1:M){
> 
>        for(y in 0:m){  
> 
> 
> 
>     
> g=lgamma(m+z)+lgamma(n[h]+a+b)+lgamma(x[h]+y+a)+lgamma(n[h]+m+b-x[h]-y)
> 
> 
>      
> g=g-lgamma(y+z)-lgamma(m-y+z)-lgamma(x[h]+a)-lgamma(n[h]+b-x[h])-
> lgamma(n[h]+m+a+b)
> 
>   
> 
>      out.h=c(out.h,h)
> 
>      out.y=c(out.y,y)
> 
>      out.m=c(out.m,m)
> 
>      out.prob=c(out.prob, exp(g))   
> 
>    out.cum=c(cumsum(out.prob))
> 
>     
> 
>  Result=data.frame(out.h,out.y,out.m,out.prob,out.cum)
> 
>  }}}}
> 
>  Kings=pp(x=c(19,20), n=c(52,60),3)
> 
>  Kings
> 
>    out.h out.y out.m   out.prob   out.cum
> 
> 1      1     0     1 0.65395431 0.6539543
> 
> 2      1     1     1 0.34604569 1.0000000
> 
> 3      1     0     2 0.43127277 1.4312728
> 
> 4      1     1     2 0.44536308 1.8766358
> 
> 5      1     2     2 0.12336415 2.0000000
> 
> 6      1     0     3 0.28672775 2.2867277
> 
> 7      1     1     3 0.43363507 2.7203628
> 
> 8      1     2     3 0.23440955 2.9547724
> 
> 9      1     3     3 0.04522764 3.0000000
> 
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.