[R] formatting a list

[jim holtman]

another choice is:

x <- scan('temp.txt', what=c(rep(list(0), 19)))

On 10/20/07, Tomas Vaisar <tvaisar at u.washington.edu> wrote:
> Hi,
>
> I am new to R and need to read in a file with 19 columns and 7000 rows
> and make it into a list of 7000 lists with 19 items each.  For a
> simpler case of 10 by 10 table I used x <-scan("file",
> list(0,0,0,0,0,0,0,0,0,0)), perhaps clumsy, but it did the job.
> However with the large 19x7000 (which needs to be transposed) I am not
> sure how to go about it.
>
> Coudl somebody suggest a way?
>
> Thanks,
>
> Tomas
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>


-- 
Jim Holtman
Cincinnati, OH
+1 513 646 9390

What is the problem you are trying to solve?