[Bioc-sig-seq] calculate alignable portion of the genome
João Fadista
Joao.Fadista at agrsci.dk
Mon May 11 11:12:45 CEST 2009
Hi Simon,
Thanks for the fast reply. It would be great if you could share your script.
Best regards,
João
-----Original Message-----
From: bioc-sig-sequencing-bounces at r-project.org [mailto:bioc-sig-sequencing-bounces at r-project.org] On Behalf Of simon andrews (BI)
Sent: Monday, May 11, 2009 10:51 AM
To: bioc-sig-sequencing at r-project.org
Subject: Re: [Bioc-sig-seq] calculate alignable portion of the genome
> -----Original Message-----
> From: bioc-sig-sequencing-bounces at r-project.org
> [mailto:bioc-sig-sequencing-bounces at r-project.org] On Behalf Of João
> Fadista
> Sent: 11 May 2009 09:36
> To: bioc-sig-sequencing at r-project.org
> Subject: [Bioc-sig-seq] calculate alignable portion of the genome
>
> Hi,
>
> I would like to know if there is any functions in Bioconductor (or
> other) that could help me calculate the alignable portion of a genome
> (not human), given a reference sequence.
> When I say alignable portion I mean that I want to know all the
> positions of the genome that can be covered uniquely by reads of 36 bp
> and up to 2 mismatches.
I recently did this for a whole human chromosome using a Perl wrapper around bowtie[1]. It could do a whole chromosome against a full genome in a few minutes, so anything smaller would be much quicker.
I'm happy to share the script I used, but you'd need to adapt it for your own needs. My script was just collecting statistics, but it would be a trivial change to make it write out the uniquely mapping fragments.
Simon.
[1] http://bowtie-bio.sourceforge.net
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